Indices and Logarithms

2. Laws of Logarithms

Laws of Logarithms

Logarithms are the inverse operations of exponents. If:

logbx=ythenby=x\log_b x = y \quad \text{then} \quad b^y = x

where bb is the base, xx is the number, and yy is the logarithm.

The fundamental laws of logarithms are as follows:


1. Product Law

logb(MN)=logbM+logbN\log_b (MN) = \log_b M + \log_b N

Example:

log2(8×4)=log28+log24\log_2 (8 \times 4) = \log_2 8 + \log_2 4

Since log28=3\log_2 8 = 3 and log24=2\log_2 4 = 2, we get:

log232=3+2=5\log_2 32 = 3 + 2 = 5

2. Quotient Law

logb(MN)=logbMlogbN\log_b \left( \frac{M}{N} \right) = \log_b M - \log_b N

Example:

log3(819)=log381log39\log_3 \left( \frac{81}{9} \right) = \log_3 81 - \log_3 9

Since log381=4\log_3 81 = 4 and log39=2\log_3 9 = 2, we get:

log39=42=2\log_3 9 = 4 - 2 = 2

3. Power Law

logb(Mn)=nlogbM\log_b (M^n) = n \log_b M

Example:

log5(253)=3log525\log_5 (25^3) = 3 \log_5 25

Since log525=2\log_5 25 = 2, we get:

log5(253)=3×2=6\log_5 (25^3) = 3 \times 2 = 6

4. Change of Base Law

logbM=logkMlogkb\log_b M = \frac{\log_k M}{\log_k b}

This is useful for converting logarithms into a different base, commonly base 10 (logarithm) or base ee (natural logarithm, denoted as ln\ln).

Example: Convert log210\log_2 10 to base 10.

log210=log1010log102\log_2 10 = \frac{\log_{10} 10}{\log_{10} 2}

Since log1010=1\log_{10} 10 = 1 and log1020.301\log_{10} 2 \approx 0.301, we get:

log210=10.3013.32\log_2 10 = \frac{1}{0.301} \approx 3.32

5. Logarithm of 1

logb1=0\log_b 1 = 0

Because any number raised to the power of zero equals 1:

b0=1b^0 = 1

Example:

log71=0\log_7 1 = 0

6. Logarithm of the Base

logbb=1\log_b b = 1

Because b1=bb^1 = b.
Example:

log44=1\log_4 4 = 1

7. Natural Logarithms (Base ee)

lnx=logex\ln x = \log_e x

Natural logarithms use the base ee (Euler’s number, approximately 2.718). The same logarithmic laws apply:

ln(MN)=lnM+lnN\ln (MN) = \ln M + \ln N ln(MN)=lnMlnN\ln \left( \frac{M}{N} \right) = \ln M - \ln N ln(Mn)=nlnM\ln (M^n) = n \ln M

Examples Using Multiple Laws

  1. Simplify log381+log39\log_3 81 + \log_3 9

    • Using the product law:

      log3(81×9)=log3729\log_3 (81 \times 9) = \log_3 729
    • Since 36=7293^6 = 729, we get:

      log3729=6\log_3 729 = 6
  2. Simplify log5125log525\log_5 125 - \log_5 25

    • Using the quotient law:

      log5(12525)=log55\log_5 \left( \frac{125}{25} \right) = \log_5 5
    • Since log55=1\log_5 5 = 1, the answer is:

      11
  3. Simplify 2log482 \log_4 8

    • Using the power law:

      log482=log464\log_4 8^2 = \log_4 64
    • Since 43=644^3 = 64, we get:

      log464=3\log_4 64 = 3